GPG-encrypted files with python

Occasionally, I want to save some data in an encrypted file from python. Using a context manager, its possible to do this quite easily and in a way where unencrypted data is never saved to disk.

I use the context manager decorator to define an encrypted file method as follows:

import StringIO
from contextlib import contextmanager

@contextmanager
def encFile(file_name, passphrase):
    a = StringIO()
    yield a
    KEYRING = './keyring.gpg'
    SECRET_KEYRING = './secring.gpg'
    GPGBINARY = 'gpg'
    gpg = gnupg.GPG(gnupghome='.', gpgbinary=GPGBINARY, keyring=KEYRING,
                    secret_keyring=SECRET_KEYRING, options=['--throw-keyids',
                    '--personal-digest-preferences=sha256','--s2k-digest-algo=sha256'])
    gpg.encoding = 'latin-1'
    ciphertext = gpg.encrypt(a.getvalue(), recipients=None, symmetric='AES256',
                             armor=False, always_trust=True, passphrase=passphrase)
    a.close()
    with open(file_name, 'wb') as f:
        f.write(ciphertext.data)

and a decrypted file method:

import StringIO
from contextlib import contextmanager

@contextmanager
def decFile(file_name, passphrase):
    KEYRING = './keyring.gpg'
    SECRET_KEYRING = './secring.gpg'
    GPGBINARY = 'gpg'
    gpg = gnupg.GPG(gnupghome='.', gpgbinary=GPGBINARY, keyring=KEYRING,
                    secret_keyring=SECRET_KEYRING, options=['--throw-keyids',
                    '--personal-digest-preferences=sha256','--s2k-digest-algo=sha256'])
    gpg.encoding = 'latin-1'
    with open(file_name, 'rb') as f:
        ciphertext = f.read()
    plaintext = gpg.decrypt(ciphertext, passphrase=passphrase, always_trust=True)
    a = StringIO(plaintext)
    a.seek(0)
    yield a
    a.close()

Now, in my code, I can just do:

with encFile(file_name, passphrase) as f:
    f.write(stuff)

or

with decFile(file_name, passphrase) as f:
    stuff = f.read()
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